Civil Engineering MCQAE Level Civil Engineering
For an activity, ES=2, LS=3, EF=7, LF=8. Total float is
Construction ManagementPYQ/PYQ-PatternMEDIUM
Choose the correct answer
A
2 days
B
5 days
C
3 days
D
1 days
Correct Answer
D. 1 days
Why is this the answer?
Total float (TF) = LS - ES = LF - EF, where LS = Latest allowable Start, ES = Earliest possible Start, LF = Latest allowable Finish, EF = Earliest possible Finish. TF = 0 implies a critical activity (on the critical path); any delay directly delays project completion. Free float = min(ES_successors) - EF of that activity. Total float = LS-ES = LF-EF = 1 days.
Related Construction Management MCQs
More solved Construction Management questions for AE/JE Civil Engineering exams.
- An activity has normal duration 10 days, normal cost Rs.8,000, crash duration 7 days...
- Which of the following is issued AFTER a contract is awarded and is NOT a tender document?
- In a lump sum contract, cost overruns due to unforeseen site conditions are borne by:
- A concrete batching plant produces 0.5 m³ per batch with a cycle time of 3 minutes....
- A brick wall is 5 m long, 4 m high and 0.35 m thick. Quantity of brick masonry is
- If concrete quantity is 5 m³ and rate is Rs. 5000/m³, amount is
Practice more Civil Engineering questions
This MCQ belongs to AE Level Premium Test Series. Full tests include timed attempts, rank comparison and subject-wise analysis.