Civil Engineering MCQJE Level Civil Engineering

In LSM, the design yield stress of Fe415 steel used in flexure calculations is:

RCCRCCEASY

Choose the correct answer

A

0.67fy

B

0.87fy

C

fy directly

D

0.75fy

Correct Answer

B. 0.87fy

Why is this the answer?

Design yield stress = fy/γm = 415/1.15 = 0.87fy = 0.87 × 415 = 361 MPa. IS 456 uses 0.87fy as the design tensile strength of steel. The factor 1.15 accounts for variability in steel strength.

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