Civil Engineering MCQJE Level Civil Engineering
In LSM, the design yield stress of Fe415 steel used in flexure calculations is:
RCCRCCEASY
Choose the correct answer
A
0.67fy
B
0.87fy
C
fy directly
D
0.75fy
Correct Answer
B. 0.87fy
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Design yield stress = fy/γm = 415/1.15 = 0.87fy = 0.87 × 415 = 361 MPa. IS 456 uses 0.87fy as the design tensile strength of steel. The factor 1.15 accounts for variability in steel strength.
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