The 'wind load' on a structure is calculated using IS 875 Part 3. The design wind pressure (pz) at height z is:
Choose the correct answer
pz = Vz/0.6
pz = 0.6Vz² (N/m²) — depends on design wind speed at height z
pz = 0.6Vb² without height correction
pz = Vb/k2
Correct Answer
B. pz = 0.6Vz² (N/m²) — depends on design wind speed at height z
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IS 875 Part 3: pz = 0.6Vz² (N/m²) where Vz = design wind speed at height z (m/s). Vz = Vb × k1 × k2 × k3 × k4 (Vb = basic wind speed, k1 = risk/return period factor, k2 = terrain roughness, k3 = topography, k4 = importance). Design wind force = Cf × Ae × pz (Cf = force coefficient). Basic wind speeds range 33–55 m/s across India.
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