Civil Engineering MCQJE Level Civil Engineering

The moment of inertia (I) of a hollow circular section with outer diameter D and inner diameter d is:

Strength of MaterialsStrength of MaterialsMEDIUM

Choose the correct answer

A

π(D⁴ + d⁴)/64

B

π(D⁴ − d⁴)/64

C

π(D² − d²)/4

D

π(D³ − d³)/64

Correct Answer

B. π(D⁴ − d⁴)/64

Why is this the answer?

I = π/64 × (D⁴ − d⁴). For hollow tube: material removed from centre reduces I. The outer fibres contribute most to I (I ∝ y⁴). Used for: column design, pipe cross-sections, circular hollow sections (CHS). Polar moment J = π/32 × (D⁴ − d⁴) = 2I for torsion.

Related Strength of Materials MCQs

More solved Strength of Materials questions for AE/JE Civil Engineering exams.

View all Strength of Materials MCQs →

Practice more Civil Engineering questions

This MCQ belongs to JE Level Premium Test Series. Full tests include timed attempts, rank comparison and subject-wise analysis.

Create Free Account