Civil Engineering MCQJE Level Civil Engineering
Approximate steel area: Mu=250 kN-m, fy=500 MPa and lever arm=550 mm. Ast required is nearest:
RCCRCC and Steel DesignHARD
Choose the correct answer
A
1045 mm²
B
522 mm²
C
209 mm²
D
909 mm²
Correct Answer
A. 1045 mm²
AI Detailed Explanation & IS Code Reference
Unlock the reasoning, formula path and code-linked notes inside your student dashboard.
Steel area from moment capacity: Ast = Mu / (0.87 × fy × z). Mu = 250 kN·m = 250.0×10⁶ N·mm, fy = 500 MPa, z = 550 mm. Ast = (250×10⁶) / (0.87 × 500 × 550) = 1045 mm². The factor 0.87 is because steel in a limit state design is stressed to 0.87fy at the ultimate state (IS 456:2000).
ScoreCardAI links this solution with subject, topic and difficulty signals so your scorecard can identify weak areas after a full mock test.
Concept shortcut
IS/IRC reference
Common trap
Practice more Civil Engineering questions
This MCQ belongs to RRB JE Civil & Allied Engineering CBT-2 Full Mock Test Series. Full tests include timed attempts, rank comparison and subject-wise analysis.