Civil Engineering MCQJE Level Civil Engineering
Applied formula case: Tensile force in steel with Ast=800 mm² and fy=415 MPa is approximately:
RCCRCC and Steel DesignHARD
Choose the correct answer
A
288.8 kN
B
332 kN
C
119.5 kN
D
1.93 kN
Correct Answer
A. 288.8 kN
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Design tensile force = 0.87 fy Ast.
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This MCQ belongs to RRB JE Civil & Allied Engineering CBT-2 Full Mock Test Series. Full tests include timed attempts, rank comparison and subject-wise analysis.