A sedimentation tank receives 10000 m³/day over surface area 250 m². Surface overflow rate is

Why is this the answer?

Surface Overflow Rate (SOR) = Q / A_s (m^3/m^2/day), where Q = daily flow rate and A_s = plan surface area of sedimentation tank. Particles with settling velocity Vs >= SOR are completely removed in an ideal rectangular tank. Typical SOR: 25–50 m^3/m^2/day for plain sedimentation. Increasing A_s for given Q improves particle removal efficiency. SOR=Q/A=10000/250=40 m³/m²/day.

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