Civil Engineering MCQAE Level Civil Engineering
Water hammer pressure rise when valve closes rapidly: ΔP = ρ×a×ΔV, where a = wave speed. For ρ=1000 kg/m³, a=1200 m/s, ΔV=2 m/s:
Fluid MechanicsPipe FlowHARD
Choose the correct answer
A
2.4 MPa
B
24 MPa
C
0.24 MPa
D
120 kPa
Correct Answer
A. 2.4 MPa
Why is this the answer?
ΔP = ρ×a×ΔV = 1000×1200×2 = 2,400,000 Pa = 2.4 MPa. This is the Joukowsky (Zhukovsky) equation for instantaneous valve closure.
Related Fluid Mechanics MCQs
More solved Fluid Mechanics questions for AE/JE Civil Engineering exams.
- The 'tsunami' is distinguished from wind waves by:
- The 'specific energy' in open channel flow is:
- The 'draft tube' in a reaction turbine (Francis/Kaplan) serves to:
- Two identical pumps in 'series' vs. 'parallel' connection:
- The 'flow net' for seepage analysis consists of:
- The 'cavitation' damage to hydraulic turbines and pump impellers appears as:
Practice more Civil Engineering questions
This MCQ belongs to Magic Mock Test Series — WBPSC AE Civil (Preliminary). Full tests include timed attempts, rank comparison and subject-wise analysis.