The conjugate beam method computes deflections by treating the M/EI diagram as:
Choose the correct answer
A load on the real beam, finding shear and moment in real beam
A distributed load on a fictitious beam (conjugate beam) with same span but modified supports; the shear in the conjugate beam = slope in real beam; moment in conjugate beam = deflection in real beam
An axial force diagram
A temperature gradient
Correct Answer
B. A distributed load on a fictitious beam (conjugate beam) with same span but modified supports; the shear in the conjugate beam = slope in real beam; moment in conjugate beam = deflection in real beam
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Conjugate beam theorem: slope at any section = shear in conjugate beam at that section; deflection = bending moment in conjugate beam. Conjugate beam supports: for real pin/roller (delta=0, theta!=0) -> free end in conjugate (V!=0, M=0); for real fixed (delta=0, theta=0) -> free end (reversed). For real free end (delta!=0, theta!=0) -> fixed end in conjugate.
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