Civil Engineering MCQAE Level Civil Engineering
The angle of principal planes is found from:
Strength of MaterialsPrincipal Plane AngleMEDIUM
Choose the correct answer
A
tan2θ=(σx−σy)/2τxy
B
tan2θ=2τxy/(σx−σy)
C
tan2θ=τxy/(σx+σy)
D
tan2θ=(σx+σy)/2τxy
Correct Answer
B. tan2θ=2τxy/(σx−σy)
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tan2θp = 2τxy/(σx−σy); gives orientation of principal planes.
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