In moment distribution method, the distribution factor (DF) for a member at a joint is:
Choose the correct answer
DF = 1/number of members at joint
DF = member stiffness / Σ(all member stiffnesses at that joint)
DF = span length / EI
DF = fixed end moment / total moment
Correct Answer
B. DF = member stiffness / Σ(all member stiffnesses at that joint)
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DF = stiffness of member / Σ stiffness at joint. Stiffness K = 4EI/L (far end fixed) or 3EI/L (far end pinned). Sum of DFs at a joint = 1.0. Unbalanced moment at joint is distributed to members in proportion to their DFs. Carry-over factor = 0.5 (to far fixed end).
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