Civil Engineering MCQCivil Engineering (Shared)
For Fe415 beam with b=250 mm and d=500 mm, minimum Ast is approximately:
Steel StructuresBeam steelMEDIUM
Choose the correct answer
A
1250 mm2
B
500 mm2
C
102 mm2
D
256 mm2
Correct Answer
D. 256 mm2
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Ast,min = 0.85bd/fy = 0.85 x 250 x 500 / 415 ≈ 256 mm2. Reference: Clause 26.5.1.1 | Page: verify from your official BIS copy/PDF pagination
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