Civil Engineering MCQAE Level Civil Engineering
For a triangular (V-notch) weir with half-angle theta and head H, the discharge is:
Fluid MechanicsNotch DischargeMEDIUM
Choose the correct answer
A
Q = (8/15) Cd sqrt(2g) tan(theta) H^(5/2)
B
Q = (2/3) Cd sqrt(2g) H^(3/2)
C
Q = Cd H^2 tan(theta)
D
Q = (8/15) Cd sqrt(g) tan(theta) H^2
Correct Answer
A. Q = (8/15) Cd sqrt(2g) tan(theta) H^(5/2)
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Triangular notch: Q = (8/15) x Cd x sqrt(2g) x tan(theta) x H^(5/2). For 90-degree V-notch (theta = 45 deg, tan = 1): Q = (8/15) Cd sqrt(2g) H^(5/2) = 1.417 H^(5/2) (with Cd = 0.611).
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