For a triangular (V-notch) weir with half-angle θ, the discharge formula is:
Choose the correct answer
Q = (2/3)Cd√(2g)LH^(3/2)
Q = (8/15)Cd√(2g)tanθ × H^(5/2) — proportional to H^5/2
Q = Cd × area × √(2gH)
Q = 1.84LH^(3/2) (rectangular formula)
Correct Answer
B. Q = (8/15)Cd√(2g)tanθ × H^(5/2) — proportional to H^5/2
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V-notch: Q = (8/15) × Cd × √(2g) × tan(θ) × H^(5/2). For 90° V-notch (θ=45°, tan45°=1): Q = (8/15) × Cd × √(2g) × H^(5/2) ≈ 1.417 × Cd × H^(5/2). More sensitive to H than rectangular (H^5/2 vs H^3/2) → better for low flow measurement. Cd for 90° sharp-edged V-notch ≈ 0.62.
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