Civil Engineering MCQAE Level Civil Engineering
For a flat belt over a fixed pulley, the ratio of tensions T1/T2 (tight side/slack side) as a function of angle of wrap theta and coefficient of friction mu is:
Engineering MechanicsBelt Friction Capstan EquationMEDIUM
Choose the correct answer
A
T1/T2 = 1 + mu x theta
B
T1/T2 = e^(mu x theta) (capstan equation)
C
T1/T2 = mu x theta
D
T1/T2 = 1/e^(mu theta)
Correct Answer
B. T1/T2 = e^(mu x theta) (capstan equation)
Why is this the answer?
Capstan equation: T1/T2 = e^(mu x theta), where theta = angle of wrap in radians, mu = coefficient of friction between belt and pulley. This is the Euler-Eytelwein formula. For rope over a fixed peg: ratio of tensions = e^(mu x theta). Used for power transmission belts, capstans, band brakes.
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