Civil Engineering MCQAE Level Civil Engineering
For a column of length L with both ends pinned, the Euler critical buckling load Pcr is:
Engineering MechanicsEuler Critical Buckling LoadMEDIUM
Choose the correct answer
A
Pcr = pi x E x I / L^2
B
Pcr = pi^2 x E x I / L^2
C
Pcr = pi^2 x E x A / L^2
D
Pcr = E x I / L
Correct Answer
B. Pcr = pi^2 x E x I / L^2
Why is this the answer?
Euler (1744): Pcr = pi^2 EI / (KL)^2, where KL = effective length (K = 1.0 for both ends pinned, 0.5 for both ends fixed, 0.7 for fixed-pinned, 2.0 for fixed-free/cantilever). Slenderness ratio lambda = KL/r (r = sqrt(I/A)). Euler formula valid only for slender columns (lambda > 100 for steel). Critical stress sigma_cr = pi^2 E / lambda^2.
Related Engineering Mechanics MCQs
More solved Engineering Mechanics questions for AE/JE Civil Engineering exams.
- Second moment of area (moment of inertia) of a rectangle (b wide, d deep) about its...
- The centroid of a semicircular area of radius R from its diameter is:
- Castigliano's second theorem is used to find the deflection (or rotation) at a point in...
- Which of the following about rigid body under coplanar forces is correct?
- D'Alembert's principle converts a dynamics problem into an equivalent statics form by...
- In the Bow notation system for graphical truss analysis (force polygons):
Practice more Civil Engineering questions
This MCQ belongs to AE Level Premium Test Series. Full tests include timed attempts, rank comparison and subject-wise analysis.