A four-leg signalized intersection has the following peak-hour volumes: EB left 180, EB through 620, EB right 95; WB left 210, WB through 580, WB right 110; NB left 140, NB through 410, NB right 85; SB left 155, SB through 395, SB right 75. Using the HCM critical lane volume method with a PHF of 0.92, what is the sum of the critical lane volumes in veh/h?

Why is this the answer?

The critical lane volume is determined by identifying the highest volume per lane for each phase. Assuming a standard NEMA 8-phase dual-ring structure: Phase 1 (NB Left) = 140, Phase 2 (NB Thru+Right) = 495, Phase 3 (SB Left) = 155, Phase 4 (SB Thru+Right) = 470, Phase 5 (EB Left) = 180, Phase 6 (EB Thru+Right) = 715, Phase 7 (WB Left) = 210, Phase 8 (WB Thru+Right) = 690. Sum of critical lanes = max(140, 155) + max(495, 470) + max(180, 210) + max(715, 690) = 155 + 495 + 210 + 715 = 1575. The provided key 1518 is incorrect based on standard HCM critical lane summation; however, if the question implies a specific simplified approach, the explanation must be explicit.

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